TSTP Solution File: NUM666^1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM666^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:56:53 EDT 2023
% Result : Theorem 3.39s 3.55s
% Output : Proof 3.39s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : NUM666^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n028.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Fri Aug 25 14:57:06 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.39/3.55 SZS status Theorem for theBenchmark.p
% 3.39/3.55 SZS output start Proof for theBenchmark.p
% 3.39/3.55 Clause #0 (by assumption #[]): Eq (some fun Xu => diffprop x y Xu) True
% 3.39/3.55 Clause #1 (by assumption #[]): Eq (moreis y z) True
% 3.39/3.55 Clause #2 (by assumption #[]): Eq (∀ (Xx Xy Xz : nat), lessis Xx Xy → (some fun Xv => diffprop Xz Xy Xv) → some fun Xv => diffprop Xz Xx Xv) True
% 3.39/3.55 Clause #3 (by assumption #[]): Eq (∀ (Xx Xy : nat), moreis Xx Xy → lessis Xy Xx) True
% 3.39/3.55 Clause #4 (by assumption #[]): Eq (Not (some fun Xu => diffprop x z Xu)) True
% 3.39/3.55 Clause #5 (by clausification #[3]): ∀ (a : nat), Eq (∀ (Xy : nat), moreis a Xy → lessis Xy a) True
% 3.39/3.55 Clause #6 (by clausification #[5]): ∀ (a a_1 : nat), Eq (moreis a a_1 → lessis a_1 a) True
% 3.39/3.55 Clause #7 (by clausification #[6]): ∀ (a a_1 : nat), Or (Eq (moreis a a_1) False) (Eq (lessis a_1 a) True)
% 3.39/3.55 Clause #8 (by superposition #[7, 1]): Or (Eq (lessis z y) True) (Eq False True)
% 3.39/3.55 Clause #9 (by clausification #[8]): Eq (lessis z y) True
% 3.39/3.55 Clause #10 (by betaEtaReduce #[0]): Eq (some (diffprop x y)) True
% 3.39/3.55 Clause #11 (by betaEtaReduce #[4]): Eq (Not (some (diffprop x z))) True
% 3.39/3.55 Clause #12 (by clausification #[11]): Eq (some (diffprop x z)) False
% 3.39/3.55 Clause #13 (by betaEtaReduce #[2]): Eq (∀ (Xx Xy Xz : nat), lessis Xx Xy → some (diffprop Xz Xy) → some (diffprop Xz Xx)) True
% 3.39/3.55 Clause #14 (by clausification #[13]): ∀ (a : nat), Eq (∀ (Xy Xz : nat), lessis a Xy → some (diffprop Xz Xy) → some (diffprop Xz a)) True
% 3.39/3.55 Clause #15 (by clausification #[14]): ∀ (a a_1 : nat), Eq (∀ (Xz : nat), lessis a a_1 → some (diffprop Xz a_1) → some (diffprop Xz a)) True
% 3.39/3.55 Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 : nat), Eq (lessis a a_1 → some (diffprop a_2 a_1) → some (diffprop a_2 a)) True
% 3.39/3.55 Clause #17 (by clausification #[16]): ∀ (a a_1 a_2 : nat), Or (Eq (lessis a a_1) False) (Eq (some (diffprop a_2 a_1) → some (diffprop a_2 a)) True)
% 3.39/3.55 Clause #18 (by clausification #[17]): ∀ (a a_1 a_2 : nat),
% 3.39/3.55 Or (Eq (lessis a a_1) False) (Or (Eq (some (diffprop a_2 a_1)) False) (Eq (some (diffprop a_2 a)) True))
% 3.39/3.55 Clause #19 (by superposition #[18, 9]): ∀ (a : nat), Or (Eq (some (diffprop a y)) False) (Or (Eq (some (diffprop a z)) True) (Eq False True))
% 3.39/3.55 Clause #20 (by clausification #[19]): ∀ (a : nat), Or (Eq (some (diffprop a y)) False) (Eq (some (diffprop a z)) True)
% 3.39/3.55 Clause #21 (by superposition #[20, 10]): Or (Eq (some (diffprop x z)) True) (Eq False True)
% 3.39/3.55 Clause #22 (by clausification #[21]): Eq (some (diffprop x z)) True
% 3.39/3.55 Clause #23 (by superposition #[22, 12]): Eq True False
% 3.39/3.55 Clause #24 (by clausification #[23]): False
% 3.39/3.55 SZS output end Proof for theBenchmark.p
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